2x^2+16-912=0

Solution for 2x^2+16-912=0 equation:

2x^2+16-912=0

We add all the numbers together, and all the variables

2x^2-896=0

a = 2; b = 0; c = -896;
Δ = b2-4ac
Δ = 02-4·2·(-896)
Δ = 7168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7168}=\sqrt{1024*7}=\sqrt{1024}*\sqrt{7}=32\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{7}}{2*2}=\frac{0-32\sqrt{7}}{4}
=-\frac{32\sqrt{7}}{4}
=-8\sqrt{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{7}}{2*2}=\frac{0+32\sqrt{7}}{4}
=\frac{32\sqrt{7}}{4}
=8\sqrt{7}
$